Java SE 8 Programmer II — Question 56

Given the code fragment:
Path file = Paths.get ("courses.txt");
// line n1
Assume the courses.txt is accessible.
Which code fragment can be inserted at line n1 to enable the code to print the content of the courses.txt file?

Answer options

• A. List<String> fc = Files.list(file); fc.stream().forEach (s - > System.out.println(s));
• B. Stream<String> fc = Files.readAllLines (file); fc.forEach (s - > System.out.println(s));
• C. List<String> fc = readAllLines(file); fc.stream().forEach (s - > System.out.println(s));
• D. Stream<String> fc = Files.lines (file); fc.forEach (s - > System.out.println(s));

Correct answer: D

Explanation

The correct answer is D because Files.lines(file) provides a stream of lines from the file, which can be directly printed using forEach. Option A is incorrect because Files.list() returns a stream of file paths, not lines from the file. Option B is incorrect as Files.readAllLines() returns a List, not a Stream. Option C fails for the same reason as B, as it attempts to use readAllLines without the proper class reference.