JNCIP-SEC: Juniper Networks Certified Professional – Security — Question 2

[edit]
useu@host# run show log debug
Feb 3 22:04:32 22:04:31.983991:CID-0:RT: ge-0/0/1.0:5.0.0.25/59028-
>25.0.0.25/23, tcp, flag 18
Feb 3 22:04:32 22:04:31.983997:CID-0:RT: find flow: table 0x582738c0, hash
53561(0xffff), sa 5.0.0.25, da 5.0.0.25, sp 59028, dp 23, proto 6, tok 20489
Feb 3 22:04:32 22:04:31.984004:CID-0:RT:Found: session id 0x14f98. sess tok
20489
Feb 3 22:04:32 22:04:31.984005:CID-0:RT: flow got session.
Feb 3 22:04:32 22:04:31.984006:CID-0:RT: flow session id 85912
Feb 3 22:04:32 22:04:31.984009:CID-0:RT: vector bits 0x2 vector 0x53a949e8
Feb 3 22:04:32 22:04:31.984012:CID-0:RT: tcp sec check.
Feb 3 22:04:32 22:04:31.984015:CID-0:RT:mbuf 0x4a82cd80, exit nh 0xa0010
Which two statements are true regarding the output shown in the exhibit? (Choose two.)

Answer options

• A. The outgoing interface is ge-0/0/1.0.
• B. The packet is subject to fast-path packet processing.
• C. The packet is part of the first-packet path processing.
• D. TCP sequence checking is enabled.

Correct answer: C, D

Explanation

The correct answers are C and D because the log indicates that the packet is undergoing first-packet path processing, which is confirmed by the presence of the session ID and flow session information. Additionally, the log mentions TCP sequence checking, indicating it is enabled. Options A and B are incorrect as there is no indication of the outgoing interface being ge-0/0/1.0 or the packet being processed in the fast-path.