AWS Certified DevOps Engineer – Professional — Question 99

A DevOps engineer must create a Linux AMI in an automated fashion. The newly created AMI identification must be stored in a location where other build pipelines can access the new identification programmatically.

What is the MOST cost-effective way to do this?

Answer options

• A. Build a pipeline in AWS CodePipeline to download and save the latest operating system Open Virtualization Format (OVF) image to an Amazon S3 bucket. Customize the image by using the guestfish utility. Use the virtual machine (VM) import command to convert the OVF to an AMI. Store the AMI identification output as an AWS Systems Manager Parameter Store parameter.
• B. Create an AWS Systems Manager Automation runbook with values instructing how the image should be created. Build a pipeline in AWS CodePipeline to execute the runbook to create the AMI. Store the AMI identification output as a Systems Manager Parameter Store parameter.
• C. Build a pipeline in AWS CodePipeline to take a snapshot of an Amazon EC2 instance running the latest version of the application. Start a new EC2 instance from the snapshot and update the running instance by using an AWS Lambda function. Take a snapshot of the updated instance and convert it to an AMI. Store the AMI identification output in an Amazon DynamoDB table.
• D. Launch an Amazon EC2 instance and install Packer. Configure a Packer build with values defining how the image should be created. Build a Jenkins pipeline to invoke the Packer build to create an AMI. Store the AMI identification output in an Amazon DynamoDB table.

Correct answer: B

Explanation

Option B is correct because it utilizes AWS Systems Manager Automation, which is designed for automated tasks and is cost-effective. The other options involve more complex processes or additional services that incur higher costs, making them less economical for this task.