AWS Certified Developer – Associate — Question 203

A company deploys a photo-processing application to an Amazon EC2 instance The application needs to process each photo in less than 5 seconds. If processing takes longer than 5 seconds, the company's development team must receive a notification.

How can a developer implement the required time measurement and notification with the LEAST operational overhead?

Answer options

• A. Create an Amazon CloudWatch custom metric. Each time a photo is processed, publish the processing time as a metric value. Create a CloudWatch alarm that is based on a static threshold of 5 seconds. Notify the development team by using an Amazon Simple Notification Service (Amazon SNS) topic.
• B. Create an Amazon Simple Queue Service (Amazon SQS) queue. Each time a photo is processed, publish the processing time to the queue. Create an application to consume from the queue and to determine whether any values are more than 5 seconds. Notify the development team by using an Amazon Simple Notification Service (Amazon SNS) topic.
• C. Create an Amazon CloudWatch custom metric. Each time a photo is processed, publish the processing time as a metric value. Create a CloudWatch alarm that enters ALARM state if the average of values is greater than 5 seconds. Notify the development team by sending an Amazon Simple Email Service (Amazon SES) message.
• D. Create an Amazon Kinesis data stream. Each time a photo is processed, publish the processing time to the data stream. Create an Amazon CloudWatch alarm that enters ALARM state if any values are more than 5 seconds. Notify the development team by using an Amazon Simple Notification Service (Amazon SNS) topic.

Correct answer: A

Explanation

Option A is the best choice as it uses Amazon CloudWatch to directly track and alert on the processing time with minimal complexity. The other options introduce unnecessary components such as SQS, SES, or Kinesis, which increase operational overhead without any added benefits for this specific requirement.